Mathematical English Usage - a Dictionary

by Jerzy Trzeciak


[see also: continue, yet

The operators An have still better smoothness properties.

The new X is no more continuous, although it still has norm 1.

An ingenious alternative proof, shorter but still complicated, can be found in [MR].

This is of course still an implicit characterization of V, since......

It seems that the solution of Problem 1 is still out of reach.

Then we can find a subsequence (still denoted by an) such that an<1 for all n.

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