[see also: as, resemble, similar
Thus modules over categories are in many ways like ordinary modules.
So we must in particular show that sets like this are not added.
It should come as no surprise that a condition like ai≠ bi turns up in this theorem.
Specifically, one might hope that a clever application of something like Choquet's theorem would yield the desired conclusion.
Construct an example, like that of Example 9, in which (1) fails but (2) holds.
It is now apparent what the solution for K will be like:......
Let us see what such a formula might look like, by analogy with Fourier series.