Mathematical English Usage - a Dictionary

by Jerzy Trzeciak


This itself does not produce a solution of (1), but an additional hypothesis such as the Palais-Smale condition does provide such a solution.

We have to show that M itself is an algebra. [Or: M is itself an algebra.]

But H itself can equally well be a member of S.

Now f is independent of the choice of γ (although the integral itself is not).

Thus in G itself there can be no such equivalences with f(r)=2.

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