John
Sharp20 The Glebe,Watford Herts WD2 6LR, England PART 3: MATHEMATICS OF TRUE GOLDEN
SECTION SPIRALSThe approximate methods, described in part 2, show the structural way of creating the spirals. This section looks at the mathematics of Golden Section spirals as it relates to the approximate methods using arcs of circles in part 2 and shows how to find the equations of the exact spirals.
Figure 30 As shown in Figure 30, the centre of rotation is found from the whirling squares diagram by intersecting diagonals of the Golden Section rectangles. These two diagonals are at right angles. That the centre is the intersection of successive diagonals of the Golden Section rectangles can be seen by the spiral symmetry of the squares and Golden Section rectangles. Although these diagonals have been drawn for the largest two rectangles, they are also the diagonals of the other Golden Section rectangles. Knowing this centre, to find the true mathematical spiral for which we have an approximation made up of arcs of circles, there are now two properties that can be used to find its equation: - the spiral goes through the point where the arcs of circles meet, that is where the squares are cut off;
- the spiral is tangent to the side of the rectangle.
These are in fact two problems yielding different results, although, as we shall see, the same spiral. The essential mathematics of the logarithmic spiral is embodied in its polar equation, previously examined in part 1: r = ae^{}q cot a.Recall that q is measured in radians,
and the constant a defines the angle
between the radius Figure 31 If we know the value of the radius at two different values of q, we can determine the value of the tangent angle a and thus define the equation. Adding some more lines to Figure 30 to create the radial vectors to points D, E, F and G of the Golden Section spiral gives us Figure 32: Figure 32 Since OE and DF are perpendicular, triangles FOE and EOD are similar; they are right triangles with hypotenuses in the ratio f. Thus so that the radii after 90º (i.e., p/2 radian) rotations are in the ratio of the Golden Section. This means that if we draw a logarithmic spiral through these points, then r = ae^{}q cot a
and fr = ae^{(}q+p/2) cot a,which, after division and taking natural logs, gives and hence a » 72.9676 degrees. For future calculations, we note the that the formula for a - given the multiplication factor, M, for a full 360º (i.e., 2p radian) rotation - may be obtained analogously, yielding ^{}-1
((ln M) / 2p);in fact, the equation for the spiral, r = aM ^{}q / 2p.While this last equation is simpler, it does not explicitly show a. Now that we have the equation and we know the pole, we can plot the true spiral through the points where the squares divide the sides of the rectangle, which gives the spiral shown in Figure 33. Figure 33 This looks remarkably similar to the one from the arcs of circles, and if the two are included in the same diagram then it is difficult to see the lines apart unless the diagram is magnified and the lines are thin. The short line sticking up at the top of Figure 33 is not a mistake. It shows an important property of the true logarithmic spiral through the points: it goes outside the rectangle, although only slightly. The short line is located at the position where the spiral cuts the rectangle when it returns inside. It is sometimes, but rarely, mentioned in descriptions of this diagram, but I have never seen either a calculation, or description, of how much. The amount it goes out is very small (only 0.165% of the shortest side of the rectangle) and so does not show up without high magnification. The area around the marked point at the top of Figure 33 shown in Figure 34. The arc of the spiral which is outside the rectangle is barely apparent, and not enough for a pencil drawing to show up. Figure 34
Figure 35 (Note that this diagram is for illustrative purposes and is not an accurate representation of how the spiral is placed in Figure 33.) The right angles triangles This means that the spiral that touches the four sides of
the rectangle is the same one as the one in Figure 32, except
that it is rotated slightly, so that it touches a little way
along the side and not at the point where the vertex square sits.
The touching point (the point equivalent to point Figure 36 The calculation of the angle of rotation is too detailed to include here, but it is slightly over 3.75°.
For the Golden Section spiral for the triangle LLS (Figure
20), the radial vector has a ratio of f
after a rotation of 108° (and hence f For the Golden Section spiral for the triangle SSL (Figure 21), the radial vector has a ratio of f after a rotation of 144°. This gives the tangent angle a » 79.1609°. For the pentagon case (Figures 28 and 29), the spiral has
a radial vector has a ratio of f Comparing the tangent angle of 72.9676° for the Golden Section spiral described by the rectangle, this shows that these four spirals, while all defined by the Golden Section, are very different.
The equation is r = (1 + 2k sin(4q/3))ae^{}kq,where If you have software for plotting curves, I welcome you to try using this equation.
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